PROBLEM SET CHEMISTRY

<!– /* Font Definitions */ @font-face {font-family:Wingdings; panose-1:5 0 0 0 0 0 0 0 0 0; mso-font-charset:2; mso-generic-font-family:auto; mso-font-pitch:variable; mso-font-signature:0 268435456 0 0 -2147483648 0;} @font-face {font-family:”MS Mincho”; panose-1:2 2 6 9 4 2 5 8 3 4; mso-font-alt:”Arial Unicode MS”; mso-font-charset:128; mso-generic-font-family:roman; mso-font-format:other; mso-font-pitch:fixed; mso-font-signature:1 134676480 16 0 131072 0;} @font-face {font-family:”\@MS Mincho”; panose-1:0 0 0 0 0 0 0 0 0 0; mso-font-charset:128; mso-generic-font-family:roman; mso-font-format:other; mso-font-pitch:fixed; mso-font-signature:1 134676480 16 0 131072 0;} /* Style Definitions */ p.MsoNormal, li.MsoNormal, div.MsoNormal {mso-style-parent:””; margin:0cm; margin-bottom:.0001pt; mso-pagination:widow-orphan; font-size:12.0pt; font-family:”Times New Roman”; mso-fareast-font-family:”Times New Roman”; mso-fareast-language:EN-US;} @page Section1 {size:612.0pt 792.0pt; margin:72.0pt 90.0pt 72.0pt 90.0pt; mso-header-margin:36.0pt; mso-footer-margin:36.0pt; mso-paper-source:0;} div.Section1 {page:Section1;} /* List Definitions */ @list l0 {mso-list-id:1275477700; mso-list-type:hybrid; mso-list-template-ids:1605148344 67698713 67698713 67698715 67698703 67698713 67698715 67698703 67698713 67698715;} @list l0:level1 {mso-level-number-format:alpha-lower; mso-level-tab-stop:36.0pt; mso-level-number-position:left; text-indent:-18.0pt;} @list l1 {mso-list-id:1609855409; mso-list-type:hybrid; mso-list-template-ids:-1426848844 67698713 67698713 67698715 67698703 67698713 67698715 67698703 67698713 67698715;} @list l1:level1 {mso-level-number-format:alpha-lower; mso-level-tab-stop:36.0pt; mso-level-number-position:left; text-indent:-18.0pt;} ol {margin-bottom:0cm;} ul {margin-bottom:0cm;} –>
/* Style Definitions */
table.MsoNormalTable
{mso-style-name:”Table Normal”;
mso-tstyle-rowband-size:0;
mso-tstyle-colband-size:0;
mso-style-noshow:yes;
mso-style-parent:””;
mso-padding-alt:0cm 5.4pt 0cm 5.4pt;
mso-para-margin:0cm;
mso-para-margin-bottom:.0001pt;
mso-pagination:widow-orphan;
font-size:10.0pt;
font-family:”Times New Roman”;
mso-ansi-language:#0400;
mso-fareast-language:#0400;
mso-bidi-language:#0400;}

XII-IPA-3 :

PROBLEM SET 1

1. Which is not a solution? brass, fog, hydrochloric acid, or wine

2. How Many Moles of CuO can be produced from 0.0450 mol if Cu2O in the following reaction? 2 Cu2O(s) + O2(g) à 4 CuO(s).

3. Methane and Oxygen react to form carbon dioxide and water. What mass of water is formed if 3.2g of Methane reacts with 12.8g of oxygen to produce 8.8g of carbon dioxide? 7.2 g, 8.8g, 14.8g, or 16.0g

4. For the reaction I2(g) à I2(s), Delta H deg = -62.4 KJ at 25 deg C.

Based on the data, at 25 deg C

a. delta H deg vap = -62.4 kJ / mol

b. delta H deg vap = 62.4 kJ / mol

c. delta H deg sub = -62.4 kJ / mol

d. delta H deg sub = -62.4 kJ / mol

5. When 200 mL of 0.150 M of hydrochloric acid is added to 125 mL of 0.175 M Mg(OH)2 the resulting solution will be? acidic, basic , or neutral

6. Calculate the energy change in kJ / mol for the reaction

Li+(g) + F- (g) à Li(g) + F(g) using the following information:

Li(g) à Li+ (g) + e- +520 kJ / mol

F(g) + e- à F-(g) -328 kJ / mol

a. -848 kJ / mol

b. -192 kJ / mol

c. + 192 kJ / mol

d. + 848 kJ / mol

7.Which statement about elemental analysis by combustion is not correct?

a, Carbon is determined from the amount of CO2 formed

b. Hydrogen is determined from the amount H2O formed

c. Oxygen is determined from the amount of H2O formed

d. Only carbon and hydrogen can be determined directly fromCO2 and H2O

8. When K2SO4(aq) and Pb(NO3)2(aq) are mixed a white colored precipitate forms, which is ? KNO3, K2SO3, Pb, or PbSO4

9. What is the Celsius temperature of 100.0g of chlorine gas in a 40.0 L container at 800mm Hg? -91 deg C, 91 deg C, 182 deg C, 364 deg C

10.Two aqueous solutions A and B, are separated by a semi permeable membrane. The pressure of solution A immediately begins to decrease. Which of the following is true?

  1. Solvent molecules a re moving from solution B into solution A
  2. The initial osmotic pressure of solution B is greater than that of solution A
  3. The solvent molecules are moving from the solution of higher osmotic pressure to that of lower osmotic pressure.
  4. Both B and C are true statements.

11. For the reaction 2CH4 (g) + 3 Cl2(g) + 3 Cl2 à 2CHCl3 (l) + 3H2 (g).

Find delta H deg f for CH4 (g).

delta H deg = -118.6 kJ.

delta H deg f = -134.1 kJ / mol for CHCl3 (l) .

  1. -193.4 kJ / mol
  2. -74.8 kJ / mol
  3. 74.8 kJ / mol
  4. 193.4 kJ /mol

PROBLEM SET 2 :


v\:* {behavior:url(#default#VML);}
o\:* {behavior:url(#default#VML);}
w\:* {behavior:url(#default#VML);}
.shape {behavior:url(#default#VML);}

st1\:*{behavior:url(#ieooui) }
<!– /* Font Definitions */ @font-face {font-family:Wingdings; panose-1:5 0 0 0 0 0 0 0 0 0; mso-font-charset:2; mso-generic-font-family:auto; mso-font-pitch:variable; mso-font-signature:0 268435456 0 0 -2147483648 0;} @font-face {font-family:”MS Mincho”; panose-1:2 2 6 9 4 2 5 8 3 4; mso-font-alt:”Arial Unicode MS”; mso-font-charset:128; mso-generic-font-family:roman; mso-font-format:other; mso-font-pitch:fixed; mso-font-signature:1 134676480 16 0 131072 0;} @font-face {font-family:”\@MS Mincho”; panose-1:0 0 0 0 0 0 0 0 0 0; mso-font-charset:128; mso-generic-font-family:roman; mso-font-format:other; mso-font-pitch:fixed; mso-font-signature:1 134676480 16 0 131072 0;} /* Style Definitions */ p.MsoNormal, li.MsoNormal, div.MsoNormal {mso-style-parent:””; margin:0cm; margin-bottom:.0001pt; mso-pagination:widow-orphan; font-size:10.0pt; font-family:”Times New Roman”; mso-fareast-font-family:”Times New Roman”; mso-fareast-language:EN-US;} h1 {mso-style-next:Normal; margin:0cm; margin-bottom:.0001pt; mso-pagination:widow-orphan; page-break-after:avoid; mso-outline-level:1; font-size:10.0pt; font-family:Arial; mso-fareast-font-family:”Times New Roman”; mso-bidi-font-family:”Times New Roman”; mso-font-kerning:0pt; mso-fareast-language:EN-US; mso-bidi-font-weight:normal;} h2 {mso-style-next:Normal; margin-top:12.0pt; margin-right:0cm; margin-bottom:3.0pt; margin-left:0cm; mso-pagination:widow-orphan; page-break-after:avoid; mso-outline-level:2; font-size:14.0pt; font-family:Arial; mso-fareast-font-family:”Times New Roman”; mso-fareast-language:EN-US; font-style:italic;} a:link, span.MsoHyperlink {color:blue; text-decoration:underline; text-underline:single;} a:visited, span.MsoHyperlinkFollowed {color:purple; text-decoration:underline; text-underline:single;} @page Section1 {size:612.0pt 792.0pt; margin:72.0pt 90.0pt 72.0pt 90.0pt; mso-header-margin:36.0pt; mso-footer-margin:36.0pt; mso-paper-source:0;} div.Section1 {page:Section1;} /* List Definitions */ @list l0 {mso-list-id:46415149; mso-list-type:simple; mso-list-template-ids:67698689;} @list l0:level1 {mso-level-number-format:bullet; mso-level-text:; mso-level-tab-stop:18.0pt; mso-level-number-position:left; margin-left:18.0pt; text-indent:-18.0pt; font-family:Symbol;} @list l1 {mso-list-id:572474908; mso-list-type:hybrid; mso-list-template-ids:-1120514096 67698689 67698691 67698693 67698689 67698691 67698693 67698689 67698691 67698693;} @list l1:level1 {mso-level-number-format:bullet; mso-level-text:; mso-level-tab-stop:36.0pt; mso-level-number-position:left; text-indent:-18.0pt; font-family:Symbol;} @list l2 {mso-list-id:632177854; mso-list-type:simple; mso-list-template-ids:67698689;} @list l2:level1 {mso-level-number-format:bullet; mso-level-text:; mso-level-tab-stop:18.0pt; mso-level-number-position:left; margin-left:18.0pt; text-indent:-18.0pt; font-family:Symbol;} @list l3 {mso-list-id:918562204; mso-list-type:simple; mso-list-template-ids:67698689;} @list l3:level1 {mso-level-number-format:bullet; mso-level-text:; mso-level-tab-stop:18.0pt; mso-level-number-position:left; margin-left:18.0pt; text-indent:-18.0pt; font-family:Symbol;} @list l4 {mso-list-id:1102259683; mso-list-type:simple; mso-list-template-ids:67698689;} @list l4:level1 {mso-level-number-format:bullet; mso-level-text:; mso-level-tab-stop:18.0pt; mso-level-number-position:left; margin-left:18.0pt; text-indent:-18.0pt; font-family:Symbol;} @list l5 {mso-list-id:1252351003; mso-list-type:simple; mso-list-template-ids:67698689;} @list l5:level1 {mso-level-number-format:bullet; mso-level-text:; mso-level-tab-stop:18.0pt; mso-level-number-position:left; margin-left:18.0pt; text-indent:-18.0pt; font-family:Symbol;} @list l6 {mso-list-id:1254628135; mso-list-type:simple; mso-list-template-ids:67698689;} @list l6:level1 {mso-level-number-format:bullet; mso-level-text:; mso-level-tab-stop:18.0pt; mso-level-number-position:left; margin-left:18.0pt; text-indent:-18.0pt; font-family:Symbol;} @list l7 {mso-list-id:1602955680; mso-list-type:simple; mso-list-template-ids:67698689;} @list l7:level1 {mso-level-number-format:bullet; mso-level-text:; mso-level-tab-stop:18.0pt; mso-level-number-position:left; margin-left:18.0pt; text-indent:-18.0pt; font-family:Symbol;} ol {margin-bottom:0cm;} ul {margin-bottom:0cm;} –>
/* Style Definitions */
table.MsoNormalTable
{mso-style-name:”Table Normal”;
mso-tstyle-rowband-size:0;
mso-tstyle-colband-size:0;
mso-style-noshow:yes;
mso-style-parent:””;
mso-padding-alt:0cm 5.4pt 0cm 5.4pt;
mso-para-margin:0cm;
mso-para-margin-bottom:.0001pt;
mso-pagination:widow-orphan;
font-size:10.0pt;
font-family:”Times New Roman”;
mso-ansi-language:#0400;
mso-fareast-language:#0400;
mso-bidi-language:#0400;}

final exam review sheet Name ________________________________

110 questions, all matching or multiple choice (scantron)

  • You will receive a formula sheet w/the equations you will need.
  • You may use a NON-TEXT STORING scientific calculator.
  • You will receive a copy of the periodic table, which will include the solubility table on the back.

Chemical Reactions

· Identify the type of reaction: Addition, Decomposition, Single Replacement, Double Replacement, or Combustion

· Predict the right side of an equation when given the left side

· Balance Equations

Chemical Composition and Stoichiometry

· Avogadro’s Number

· Moles

· Molecular Weight

· Convert moles to grams

· Convert grams to moles

· Convert atoms/molecules to moles

· Convert moles to atoms/molecules

· Find the empirical and molecular formula of a compound

· Find the percent composition of a compound

· Find a mole ratio

· Convert moles/grams of a substance to moles/grams of a different substance (stoichiometry)

· Find the limiting reactant & calculate product based on limiting reactant

· Calculate percent yield and percent error

Gas Laws

· Know units of pressure: mm Hg, in Hg, atm, torr

· Know units of volume: mL, L

· Convert Celcius to Kelvin

· Solve combined gas law problems

· Solve ideal gas law problems

· Solve Dalton’s Law of Partial Pressures problems

· Use molar volume of a gas (22.4 L = 1 mole at STP) to do stoichiometry

· Convert to and from STP

Solutions

· Define: soluble, solute, solvent, solution, electrolyte, nonelectrolyte, saturated, unsaturated, supersaturated

· Calculate Molarity.

· Calculate molality.

· Calculate % by mass

· Calculate changes in freezing point and boiling point

· Calculate the solute and solvent necessary for a dilution

· Calculate the volume necessary to neutralize an acid/base

Acids and Bases

· Know properties of acids and bases and which ones are considered strong acids

· Know definitions of acids and bases according to Arrhenius, Bronsted-Lowry, and Lewis.

· Review naming of acids, both binary and ternary.

· Calculate pH, pOH, H+ concentration, and OH- concentration for either a strong or weak acid or base.

· Label Bronsted-Lowry acid-base reactions as acid, base, conjugate acid, and conjugate base.


Chemistry I-2 HD Final Exam Formula Sheet

Stoichiometry:

% yield = actual mass of product X 100

theoretical mass of product

% error = | actual – theoretical | X 100

theoretical

Gas Laws:

Ideal Gas Law: PV = nRT

R = 0.0821 L*atm/mol*K

Combined Gas Law: P1V1 = P2V2

T1 T2

Dalton’s Law of Partial

Pressures: Ptot = Pa + Pb + Pc

Graham’s Law:

Solutions:

Molarity = mol solute Molality = mol solute % mass = g solute

L solution kg solvent g solution

Freezing point change: ΔT = Kf*m*i

Boiling point change: ΔT = Kb*m*i

Dilution/Titration formula: M1V1 = M2V2

Acids/Bases:

pH = -log [H+]

pOH = -log [OH]

pH + pOH = 14

<!– /* Font Definitions */ @font-face {font-family:”MS Mincho”; panose-1:2 2 6 9 4 2 5 8 3 4; mso-font-alt:”Arial Unicode MS”; mso-font-charset:128; mso-generic-font-family:roman; mso-font-format:other; mso-font-pitch:fixed; mso-font-signature:1 134676480 16 0 131072 0;} @font-face {font-family:”\@MS Mincho”; panose-1:0 0 0 0 0 0 0 0 0 0; mso-font-charset:128; mso-generic-font-family:roman; mso-font-format:other; mso-font-pitch:fixed; mso-font-signature:1 134676480 16 0 131072 0;} /* Style Definitions */ p.MsoNormal, li.MsoNormal, div.MsoNormal {mso-style-parent:””; margin:0cm; margin-bottom:.0001pt; mso-pagination:widow-orphan; font-size:10.0pt; font-family:”Times New Roman”; mso-fareast-font-family:”Times New Roman”; color:windowtext; mso-fareast-language:EN-US;} h1 {mso-style-next:Normal; margin:0cm; margin-bottom:.0001pt; mso-pagination:widow-orphan; page-break-after:avoid; mso-outline-level:1; font-size:10.0pt; font-family:Arial; mso-fareast-font-family:”Times New Roman”; mso-bidi-font-family:”Times New Roman”; color:windowtext; mso-font-kerning:0pt; mso-fareast-language:EN-US; font-weight:bold; mso-bidi-font-weight:normal;} p {mso-margin-top-alt:auto; margin-right:0cm; mso-margin-bottom-alt:auto; margin-left:0cm; mso-pagination:widow-orphan; font-size:12.0pt; font-family:”Times New Roman”; mso-fareast-font-family:”Times New Roman”; color:black; mso-fareast-language:EN-US;} @page Section1 {size:612.0pt 792.0pt; margin:72.0pt 90.0pt 72.0pt 90.0pt; mso-header-margin:36.0pt; mso-footer-margin:36.0pt; mso-paper-source:0;} div.Section1 {page:Section1;} –>
/* Style Definitions */
table.MsoNormalTable
{mso-style-name:”Table Normal”;
mso-tstyle-rowband-size:0;
mso-tstyle-colband-size:0;
mso-style-noshow:yes;
mso-style-parent:””;
mso-padding-alt:0cm 5.4pt 0cm 5.4pt;
mso-para-margin:0cm;
mso-para-margin-bottom:.0001pt;
mso-pagination:widow-orphan;
font-size:10.0pt;
font-family:”Times New Roman”;
mso-ansi-language:#0400;
mso-fareast-language:#0400;
mso-bidi-language:#0400;}

Review Problem Set Name ___________________________

Balance these equations:

1. _____Ca(OH)2(s) + _____HCl(aq) —> ____CaCl2(aq) + _____H2O(l)

2. _____Ag2O(s) —> _____Ag(s) + _____O2(g)

3. _____C4H10(g) + _____O2(g) —> _____CO2(g) + _____H2O(g)

Find the molecular weight of each compound.

4. BaI2

5. AgC2H3O2

Convert.

6. 0.4 moles of Sn to atoms

7. 32 g of K2O to molecules

8. 800 g of CaCl2 to moles

9. 0.75 moles of H2O to grams

10. 9.0 g of Cl2 to atoms

Find the percent composition for each element in the compound.

11. Mn2O7

12. AuNO3

Empirical and Molecular Formulas

13. NutraSweet is 57.14% C, 6.16% H, 9.52% N, and 27.18% O.  Calculate the empirical formula of NutraSweet and find the molecular formula.  (The molar mass of NutraSweet is 294.30 g/mol)

Stoichiometry

14. Na + I2 —> NaI

If 2.8 grams of sodium were used for the reaction, and an excess of iodine was present, how many moles of sodium iodide would be produced?

15. Pb(NO3)2 + K2CrO4 –> PbCrO4 + 2 KNO3

If you started with 0.97 g of K2CrO4 and excess Pb(NO3)2, how many grams of KNO3 could be produced?

15 ½ . Given the following reaction: (hint: balance!)

C3H8 +    O2 ——->     CO2 +     H2O

If you start with 14.8 g of C3H8 and 3.44 g of O2,

a)  determine the limiting reagent
b)  determine the number of moles of carbon dioxide produced
c)  determine the number of grams of H2O produced
d)  determine the number of grams of excess reagent left


Reactions. Complete and balance.

16. K2CO3 + BaCl2 —>

17. NaCl + O2 —>

18. Zn(CO3) —>

19. RaCl2 —>

20. C6H6 + O2 —>

21. Ra + Cl2 —>

Gases. Solve.

22. Given 500 cm3 of methane gas at 2.5 atm and 20 oC. What would be the volume of the gas at STP?

23. What pressure is exerted by 2 moles of a gas in a 500 cm3 container at 25 oC?

24. Two hundred cubic centimeters of a gas are collected by water displacement. The conditions at time are 1.1 atm and 30 oC. The vapor pressure of water at 30 oC is 23.4 mm Hg. What would be the pressure of the dry gas?

25. 2 C2H6 + 7 O2 –> 4 CO2 + 6 H2O

How many milliliters of ethane (C2H6) at STP are required to produce 22 g of carbon dioxide?

Solutions.

26. A solution is prepared by mixing 10.0 grams of benzene (C6H6) in 150 g of water to create a solution total volume of 102 ml. Calculate the molarity, mass percent, and molality of benzene in the solution.

27. 1 gram of salt (NaCl) is added to 100 mL of water. What are the new freezing and boiling points? (Kb = 0.51 oC kg/mol, Kf = 1.86 oC kg/mol)

28. If I dilute 200 mL of 0.10 M lithium acetate solution to a volume of 750 mL, what will the concentration of this solution be?

29. How many milliliters of 0.100 M HCl are required to neutralize 25.0 mL of 0.100 M Ba(OH)2?

Name the following acids.

30. H3PO3 ____________________________________________

31. HCl ____________________________________________

32. H2Se ____________________________________________

33. HNO2 ____________________________________________

34. H2CO3 ____________________________________________

Solve.

35. [H+] = 5.32 X 10 -6

[OH‑] =

pH =

pOH =

Acid or Base? _______

36. [H+] =

[OH‑] = 8.32 X 10 -12

pH =

pOH =

Acid or Base? _______


Bronsted-Lowry Pairs

Label each compound in the equation using the following terms: acid, base, conjugate acid, conjugate base.

37. NH3 + H2O <===> NH4+ + OH¯

38. HNO2 + H2O <===> H3O+ + NO2¯

pH of strong/weak acids/bases

Find the pH of each of the following.

39. 1.2M HCl

40. 0.15M CH3NH2 (Kb = 4.4 X 10-4)

Tinggalkan komentar

Belum ada komentar.

Comments RSS TrackBack Identifier URI

Tinggalkan Balasan

Isikan data di bawah atau klik salah satu ikon untuk log in:

Logo WordPress.com

You are commenting using your WordPress.com account. Logout / Ubah )

Gambar Twitter

You are commenting using your Twitter account. Logout / Ubah )

Foto Facebook

You are commenting using your Facebook account. Logout / Ubah )

Foto Google+

You are commenting using your Google+ account. Logout / Ubah )

Connecting to %s